x^2/9y^4/z^7/2z^4*4y^2/x^6=28

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Solution for x^2/9y^4/z^7/2z^4*4y^2/x^6=28 equation: 


D( x )

z^7 = 0

x^6 = 0

z^7 = 0

z^7 = 0

z^7 = 0

x naleu017Cy do R

x^6 = 0

x^6 = 0

1*x^6 = 0 // : 1

x^6 = 0

x = 0

x belongs to the empty set

(4*y^2*(((((x^2)/9)*y^4)/(z^7))/2)*z^4)/(x^6) = 28

x belongs to the empty set

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